# Find the dimensions of a rectangle

by a visitor

**Question**

The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what is the dimensions of the rectangle?

**Answer**

The picture below shows the rectangle with the area of 45cm

^{2}. Now, let the width be

**w**. Since, the length is 4cm greater than the width, the length will be

**w+4** cm.

Before we can find the dimensions of the rectangle, we need find

**w** first. Here's how:

**1) Write an equation that relates ***45cm*^{2}, w+4 and w.To do so, we know that the area of the rectangle, 45cm

^{2} can be found by multiplying

**w** with

** w+4**. Hence, we have:

To continue, we need to remove the bracket and simplify the equation. This is shown below:

**2) Solve the Quadratic Equation**Notice that, now we have a quadratic equation:

To find

**w**, we need to solve the quadratic equation. One way to do so is to

factorize the quadratic equation. Hence, we have:

Now, since

**w** is the width of a rectangle. There is no way it can be a negative number. Therefore,

**w** must be 5.

With

**w** = 5. The...

...and the...

Below is the rectangle with its dimensions: