# Problem Solving - Find the total time to paint a house

**Question**

If Sally can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together?

**Answer**

**STEP 1: **Analyzing the given problem is the first step to be done. You are given the time taken by the two people to paint the house. With these values, the part of work done by each person in an hour can be found. (Recall that the rate of work done is the reciprocal of time taken.)

Sally paints the house in 4 hours. So, the part of the work that she completes in 1 hour will be

^{1}/

_{4}. Similar is the case with John. He completes

^{1}/

_{6} of the work in an hour.

The total work done by the two people is the

sum of the rates.

**STEP 2: **You see that the denominators of the fractions in the left are not the same. To be able to perform the addition, we need fractions with like denominators (

equivalent fractions). If we multiply the first fraction by

^{3}/

_{3}, and the second by

^{2}/

_{2}, we can get equivalent fractions.

Now, simply add the numerator of the fractions keeping the denominator.

**STEP 4: **You have the total amount of work done by the two as

^{5}/

_{12}. But, what you require to find is the time taken. The reciprocal of

^{5}/

_{12} will give the desired result.

In

**2.4 hours**, the two people together will finish painting the house.