Vertex of a Quadratic Equation
Lesson Objective
In this lesson, we will learn how to find the vertex of a quadratic equation.
About This Lesson
In this lesson, we will:
 Learn what is the vertex of a quadratic equation.
 Learn the formula to find the xcoordinate of the vertex.
 See some examples on using the formula to find the coordinates of the vertex.
The study tips and math video below will explain more.
Study Tips
Tip #1
The general quadratic equation is given as:
Where a, b and c are the coefficients of each term respectively. Now, the graph of a quadratic equation will always have a highest point or a lowest point depending on the value of a. This point is called the Vertex. The pictures below will illustrate this.

Graph with a Highest Point

Graph with a Lowest Point
Tip #2  Vertex Formula
The formula to find the xcoordinate of the vertex is shown below:
Where a and b are the coefficients in the general quadratic equation shown below:
Math Video
Lesson Video
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00:00:04.130
In this lesson, we will learn about the vertex of a quadratic equation.
00:00:09.240
Now, this is the graph of the quadratic equation, y= x^2 +2x.
00:00:17.160
Notice that, this is the highest point on the graph. Hence, this point is the vertex of a quadratic equation.
00:00:27.000
Also, if you have a quadratic graph as shown here, the lowest point, is also the vertex of the quadratic equation, y = 2x^2 8x +3.
00:00:38.160
Now, there is a formula to calculate the xcoordinate of the vertex of a quadratic equation.
00:00:44.090
The formula is, x = b/2a. Now, what are 'a' and 'b'? Let's find out.
00:00:54.010
The general equation of a quadratic equation is given as, y = ax^2 +bx, +c. Where, 'a', 'b' and 'c' are the coefficients for each term respectively.
00:01:10.140
Let's see an example on using this formula, by using this equation, y = 2x^2 8x +3.
00:01:20.180
To find out the values of 'a', 'b' and 'c', we can rewrite this equation as, y = 2x^2 + (8)x +3.
00:01:32.200
By comparing this equation with the general equation, we can see that, 'a' is equals to 2, 'b' is equals to 8, and 'c' is equals to 3.
00:01:44.200
Knowing this, we can substitute 'b', with 8, and substitute 'a', with 2. Now, we can simplify this term.
00:01:57.000
This term is the same as, [(8)]/[2(2)]. Negative multiply bracket 8, gives 8. 2 multiply with 2, gives 4. 8 divide by 4, gives 2
00:02:17.090
Finally, we have x equals to 2. With this, we know that the vertex of the quadratic equation has the xcoordinate of 2.
00:02:27.220
Let's go back to the original equation. Now, we can use the x–coordinate to find the ycoordinate of the vertex.
00:02:38.060
To do so, we can substitute x with 2. 8 multiply with 2, gives 16. Adding 16 with 3, gives 13.
00:02:53.150
Again, we can substitute x with 2. 2^2 is the same as, 2 multiply by 2. Which is equals to 4. Let’s write down this number.
00:03:08.100
Let's continue. 2 multiply with 4, gives 8. 8 minus 13, gives 5.
00:03:20.170
Hence, the vertex has ycoordinate of 5. This ycoordinate is located here.
00:03:30.080
Hence, the vertex of the equation has the coordinates of (2, 5).
00:03:40.080
Let's see another example. Consider the quadratic equation, y = x^2 +2x. The graph for this equation is shown here.
00:03:54.170
Now, the vertex is located at the highest point on the graph. Let's find the coordinates of this vertex.
00:04:03.210
Again, we start with the formula for the xcoordinate of the vertex of a quadratic equation, x = b/2a.
00:04:13.050
To find the values of 'a' and 'b', we can compare this equation with the general equation, y = ax^2 + bx +c.
00:04:24.230
For easier comparison, we can rewrite this quadratic equation as, y = 1x^2 +4x + 0. Hence, we can see that, 'a' is equals to 1, ‘b’ is equals to 2, and 'c' is equals to 0.
00:04:44.120
Knowing this, we can substitute 'b' with 2 and substitute 'a' with 1.
00:04:53.170
Let's simplify this term. Now, this term is the same as, 2/2(1). 2 multiply by 1, gives 2. 2 divides by 2, gives 1. Hence, we have, x equals to 1.
00:05:19.130
With this, the vertex has the xcoordinate of 1. Let's change back to the original equation.
00:05:27.130
Now, we can use this xcoordinate to find the ycoordinate of the vertex. Here’s how. Substitute x with 1. 2 multiply with 1, gives back 2.
00:05:43.240
Let's continue. Again, substitute x with 1. 1^2, is the same as, 1 multiply with 1. This gives 1. Let’s write this down.
00:06:01.170
Finally, 1 add with 2, gives 1.
00:06:07.000
Hence, the ycoordinate of the vertex is 1. This can be seen here.
00:06:15.070
Hence, the coordinates of the vertex of this quadratic equation is (1, 1).
00:06:24.010
That is all for this lesson. Try out the practice question to test your understanding.
Practice Questions & More
Multiple Choice Questions (MCQ)
Now, let's try some MCQ questions to understand this lesson better.
You can start by going through the series of questions on vertex of a quadratic equation or pick your choice of question below.
 Question 1 on finding the vertex of a quadratic equation
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