Word Problem - Dimes and Nickels
Dave has a total of $4.50. He has twice as many dimes as nickels. How many of each coin does he have?
Before we can solve this problem, we should know that a nickel is worth 5 cents ($0.05) and a dime is worth 10 cents ($0.10). Now, we can start solving this question by analyzing the following sentence:
...Dave has...twice as many dimes as nickels .....
The above sentence means that the number of dimes are 2 times more than the number of nickels. With this, we can start forming an equation related to the dimes and nickels.
First, let's number of nickels be y
So, the value of all the nickels in dollars:
0.05 × y = 0.05y
Since the number of dimes are 2 times more than the number of nickels, the number of dimes will be 2y
So, the value of all the dimes in dollars:
0.10 × 2y = 0.20y
Now, by adding the value of nickels and dimes, we can get an equation for the total values ($4.50) of the dimes and nikels:
0.05y + 0.20y = 4.50
With this equation, we can find the value of y:
Number of nickels = y = 18
Number of dimes = 2y = 2(18) = 36