### Solving Linear Equation Practice Question #### Question 2

Solve the following linear equation:  A. +3
B. -3
C. -2
D. 2

### Step by Step Solution

• #### Step 1

To solve the linear equation, add -3 to both sides of the equation to remove +3. The equation becomes:

r +3 -3 = 9 -2r -3

Now, on the Left Hand Side (LHS) of the equation, +3 and -3 cancels off. We are left with :

r = 9 -2r -3 • #### Step 2

Keeping the objective in mind, r = ?, we need to remove -2r on the Right Hand Side (RHS) of the equation. Hence, adding +2r to both sides:

r +2r = 9 -2r +2r -3

Now, on the RHS, -2r and +2r cancels off. We are left with:

r +2r = 9 -3 • #### Step 3

Now, we can simplifying the terms on the LHS by adding r and 2r. This gives 3r.

3r = 9 -3

Similarly, simplifying the terms in the RHS adding 9 and -3. This gives 6

3r = 6 • #### Step 4

Realize that to get r = ?, we need to remove 3 from 3r. To do so, we can divide both sides by 3 as shown in the picture. Now, on the LHS, the we 3 divides by 3 cancels off. So, we are left with r = 6/3. • #### Step 5

Now, on the RHS, 6/3 gives 2. Finally, we have r = 2. 